![Java并发编程:核心方法与框架](https://wfqqreader-1252317822.image.myqcloud.com/cover/235/822235/b_822235.jpg)
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![](https://epubservercos.yuewen.com/D3D8F4/4410924203007901/epubprivate/OEBPS/Images/icon1.png?sign=1738886919-3XRBi2rVQ7zAd2sKbwOy35JeN0g6ajMQ-0-16ac5ece0ad688577385eb6b58f5c51b)
1.1.11 方法tryAcquire(int permits, long timeout, TimeUnit unit)的使用
有参方法tryAcquire(int permits, long timeout, TimeUnit unit)的作用是在指定的时间内尝试地获得x个许可,如果获取不到则返回false。
创建Java项目Semaphore_tryAcquire_4,将项目Semaphore_tryAcquire_3中的源代码复制到Semaphore_tryAcquire_4中,更改类Service.java代码如下:
package service; import java.util.concurrent.Semaphore; import java.util.concurrent.TimeUnit; public class Service { private Semaphore semaphore = new Semaphore(3); public void testMethod() { //1改成3 try { if (semaphore.tryAcquire(3, 3, TimeUnit.SECONDS)) { System.out.println("ThreadName=" + Thread.currentThread().getName() + "首选进入!"); for (int i = 0; i < Integer.MAX_VALUE; i++) { String newString = new String(); Math.random(); } //方法release对应的permits值也要更改 semaphore.release(3); } else{ System.out.println("ThreadName=" + Thread.currentThread().getName() + "未成功进入!"); } } catch(InterruptedExceptione){ e.printStackTrace(); } } }
程序运行后的效果如图1-22所示。
![](https://epubservercos.yuewen.com/D3D8F4/4410924203007901/epubprivate/OEBPS/Images/figure_0031_0001.jpg?sign=1738886919-lQCaKzRrzlrnNNOMzYWjBI52IOjY5618-0-75b09e7d0495600d921913d9d9389bf8)
图1-22 线程B未获得许可
更改Service.java类代码如下:
for (int i = 0; i < Integer.MAX_VALUE; i++) { }
程序运行结果如图1-23所示。
![](https://epubservercos.yuewen.com/D3D8F4/4410924203007901/epubprivate/OEBPS/Images/figure_0031_0002.jpg?sign=1738886919-Sd1b4PqNBHSRe48BGYKjBRJ4E4wQfH79-0-048c499925c79cb47f4a30327fc86ada)
图1-23 都获得许可